Understanding Binomial Distribution

🎯 What is Binomial Distribution?

The Binomial Distribution is a discrete probability distribution used to model the number of successes in a fixed number of independent experiments — where each experiment (called a Bernoulli trial) has only two outcomes:

• Success
• Failure

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📚 This post is part of the "Intro to Statistics" series

🔙 Previously: Understanding Z-Distribution and Using the Z-Table

🔜 Next: From Sample to Population: Basics of Sampling in Statistics

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⚙️ Conditions for a Binomial Experiment

For a scenario to follow a binomial distribution, two essential conditions must be met:

1. The probability of success \( p \) is constant for every trial.
2. The trials are independent — the outcome of one does not affect the others.

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🧱 Components of a Binomial Experiment

A binomial distribution is built on the following:

1. A Bernoulli trial: one trial with two possible outcomes (Success or Failure) and constant probability \( p \).
2. Observe \( n \) such trials.
3. Count the number of successes: \( x \).

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📐 The Binomial Probability Mass Function (PMF)

The binomial formula calculates the probability of exactly \( x \) successes in \( n \) trials:

\[ P(X = x) = \binom{n}{x} p^x (1 - p)^{n - x} \]

Where:

• \( \binom{n}{x} = \frac{n!}{x!(n - x)!} \) is the number of combinations (“n choose x”)
• \( p \) is the probability of success
• \( 1 - p \) is the probability of failure

This is a probability mass function because it deals with discrete values.

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🧮 Example: Tossing a Biased Coin

Suppose a coin has a 70% chance of landing heads (success). You flip it 5 times. What is the probability of getting exactly 3 heads?

Let:

• \( n = 5 \)
• \( x = 3 \)
• \( p = 0.7 \)

Then: \[ P(X = 3) = \binom{5}{3} (0.7)^3 (0.3)^2 = 10 \times 0.343 \times 0.09 = 0.3087 \]

So, there’s a 30.87% chance of getting exactly 3 heads.

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📈 Cumulative Binomial Probability

To find the probability of at most \( x \) successes:

\[ P(X \leq x) = \sum_{k=0}^{x} \binom{n}{k} p^k (1 - p)^{n - k} \]

🔍 Example:

You flip a fair coin \( n = 4 \) times. What’s the probability of getting at most 2 heads? Let \( p = 0.5 \)

\[ P(X \leq 2) = P(X=0) + P(X=1) + P(X=2) \]

Compute each:

• \( P(X=0) = \binom{4}{0}(0.5)^0(0.5)^4 = 1 \times 1 \times 0.0625 = 0.0625 \)
• \( P(X=1) = \binom{4}{1}(0.5)^1(0.5)^3 = 4 \times 0.5 \times 0.125 = 0.25 \)
• \( P(X=2) = \binom{4}{2}(0.5)^2(0.5)^2 = 6 \times 0.25 \times 0.25 = 0.375 \)

\[ P(X \leq 2) = 0.0625 + 0.25 + 0.375 = 0.6875 \]

So, there’s a 68.75% chance of getting 2 or fewer heads.

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🧭 Symmetry and Skewness

The shape of a binomial distribution depends on the probability ( p ):

• If \( p = 0.5 \): the distribution is symmetric.
• If \( p < 0.5 \): it is right-skewed.
• If \( p > 0.5 \): it is left-skewed.

The spread is widest when the distribution is symmetric (i.e., ( p = 0.5 )).

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📊 Mean and Standard Deviation

The Mean (Expected Value) and Standard Deviation give insights into the center and spread of the distribution:

✅ Mean (\( \mu \)):

\[ \mu = n \cdot p \] This tells us the average number of successes over many trials.

✅ Standard Deviation (\( \sigma \)):

\[ \sigma = \sqrt{n \cdot p \cdot (1 - p)} \] This quantifies the variability around the mean.

📌 Example:

You roll a die 12 times. The chance of rolling a 6 (success) is \( p = \frac{1}{6} \). What are the mean and standard deviation?

• \( n = 12 \)
• \( p = \frac{1}{6} \)

\[ \mu = 12 \cdot \frac{1}{6} = 2 \] \[ \sigma = \sqrt{12 \cdot \frac{1}{6} \cdot \frac{5}{6}} = \sqrt{1.6667} \approx 1.29 \]

So, you expect on average 2 sixes, with a standard deviation of about 1.29.

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🧠 Level Up: When to Use the Binomial Model

• The binomial model is perfect for yes/no, win/lose, pass/fail scenarios.
• It's used in genetics, quality control, clinical trials, and surveys.
• When \( n \) is large and \( p \) isn't too close to 0 or 1, the binomial distribution approximates the normal distribution.
• Use statistical software or binomial calculators when \( n \) is big or cumulative probabilities are needed.

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📌 Try It Yourself: Binomial Distribution

Q1: A binomial experiment has \( n = 10 \) and \( p = 0.6 \). What is the expected number of successes?

💡 Show Answer

• A) 4
• B) 6 ✓
• C) 10
• D) 0.6

Q2: Which of the following conditions is not required for a binomial distribution?

💡 Show Answer

• A) Fixed number of trials
• B) Two outcomes per trial
• C) Changing probability of success ✓
• D) Independent trials

Q3: What is the formula for the standard deviation of a binomial distribution?

💡 Show Answer

• A) \( \mu = np \)
• B) \( \sigma = \sqrt{np(1 - p)} \) ✓
• C) \( \sigma = np^2 \)
• D) \( \sigma = n \cdot p \cdot (1 - p) \)

Q4: When \( p = 0.9 \) and \( n = 20 \), what is the shape of the distribution?

💡 Show Answer

• A) Symmetric
• B) Left-skewed ✓
• C) Right-skewed
• D) Uniform

Q5: Which of the following is a discrete probability distribution?

💡 Show Answer

• A) Normal distribution
• B) Binomial distribution ✓
• C) Exponential distribution
• D) Uniform (continuous) distribution

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✅ Summary

Concept	Description
Binary Outcome	Each trial has two outcomes: success or failure
Bernoulli Trial	A single trial with constant \( p \)
PMF	Formula: \( \binom{n}{x} p^x (1 - p)^{n - x} \)
Cumulative Probability	\( P(X \leq x) = \sum_{k=0}^x \binom{n}{k} p^k (1-p)^{n-k} \)
Symmetry & Skewness	Depends on \( p \): symmetric if \( p=0.5 \), right-skewed if \( p < 0.5 \), left-skewed if \( p > 0.5 \)
Mean & Std. Dev.	\( \mu = np \), \( \sigma = \sqrt{np(1-p)} \)

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🔜 Up Next

Next, we’ll explore the Sampling Distribution of the Sample Mean — a fundamental concept in inferential statistics used to understand how sample means behave.

Stay curious!